Particle travelling in magnetic field unit vectors

Click For Summary
SUMMARY

A particle with a charge of -2.00 C moving with a velocity vector of v = 1.00 i^hat + 7.00 j^hat encounters a magnetic field B = 60.00 k^hat T. The force on the particle is calculated using the equation F = Q (v x B), resulting in F = -840i + 120j. The discrepancy in signs from the provided answer is attributed to the negative charge of the particle, which necessitates a reversal in the direction of the force as confirmed by the right-hand rule adjusted for negative charges.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with the Lorentz force equation
  • Knowledge of the right-hand rule for magnetic forces
  • Basic principles of electromagnetism
NEXT STEPS
  • Study vector cross product calculations in detail
  • Learn more about the Lorentz force and its applications
  • Explore the implications of charge polarity in magnetic fields
  • Investigate the right-hand rule and its variations for different charge types
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the behavior of charged particles in magnetic fields.

bmxicle
Messages
51
Reaction score
0

Homework Statement


a particle with charge -2.00 C initially moves at v = 1.00 i^hat + 7.00 j^hat. If it encounters a magnetic field B = 60.00 k^hat T, find the force on the particle


Homework Equations


F = Q (v x B)


The Attempt at a Solution


I set up a matrix to find the cross product.

v x B = det i j k
1 7 0
0 0 60

If you expand along row three you get (-1)^(3+3) * (60) det i j
1 7

= 60(7i-1j)

===> F=(-2.0 C)(60)(7i - 1j) = -840i + 120 j

The answer i was given has the signs reversed, and i can't figure out why. I've tried it drawing diagrams too and i still got the same answer.
 
Physics news on Phys.org
bmxicle said:

Homework Statement


a particle with charge -2.00 C initially moves at v = 1.00 i^hat + 7.00 j^hat. If it encounters a magnetic field B = 60.00 k^hat T, find the force on the particle


Homework Equations


F = Q (v x B)


The Attempt at a Solution


I set up a matrix to find the cross product.

v x B = det i j k
1 7 0
0 0 60

If you expand along row three you get (-1)^(3+3) * (60) det i j
1 7

= 60(7i-1j)

===> F=(-2.0 C)(60)(7i - 1j) = -840i + 120 j

The answer i was given has the signs reversed, and i can't figure out why. I've tried it drawing diagrams too and i still got the same answer.

I think you're right. Whatever answer you were given probably did not take into account the negative charge.

Using the right hand rule (and then flipping your hand 180-deg because a negative particle) confirms your answer qualitatively.
 
thanks, i was wondering if that was the case.
 

Similar threads

Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
26
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
8
Views
2K
Replies
2
Views
1K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K