Partition Function Homework: Find Entropy Change for Isothermal Expansion

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SUMMARY

The discussion focuses on calculating the change in entropy for one mole of gas undergoing isothermal expansion, governed by the van der Waals equation of state: (P + a/V²)(1 - b/V) = RT/V. The correct approach involves integrating the pressure derived from this equation, rather than using the ideal gas law. The initial attempt incorrectly applied the ideal gas equation, leading to an erroneous result. The correct entropy change formula is derived from the proper equation of state, emphasizing the importance of using the right thermodynamic principles.

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Homework Statement



One mole of a gas obeys the equation of state
(P +a/V2 )(1 −b/V) =RT/V
Find the change in entropy if one mole of the gas is isothermally expanded until the volume
is doubled. Express your answer in terms of the initial volume of the gas Vi.

Homework Equations



S2-S1=1/T Integral from Vi to 2Vi of PdV

The Attempt at a Solution



I replaced P with P=NkT/V

that leads to

S2-S1=-kln(2Vi/Vi)

as the answer was asked for in terms of Vi I'm not sure that's rightsorry titled the question wrong meant to title other Q as partition function
 
Last edited:
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That is not right.

You are using the wrong equation of state.

It is stated in problem that the gas obeys a different equation of state, not the usual, PV=NkT.

You have to use the given equation of state to express P in terms of V.
 
By the way, that equation of state is called the van der Waals equation. It takes into account intermolecular forces and the volume of molecules instead of assuming an ideal gas.
 

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