Patch of a surface in spherical coordinates?

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theBEAST
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Homework Statement


I am currently trying to prove:

S = ∫∫a2sinΦdΦdθ

Here is my work (note that in my work I use dS instead of S, this is an accident):
Handwritten derivation on paper of a spherical shell volume element dV = ρ² sinφ dρ dθ dφ, expanding ρ³ from a to a+da, then a surface element dS = ∫∫ a² da sinφ dθ dφ compared with a notes formula, with a small sphere diagram showing axes and dθ.


I end up with:

S = ∫∫a*da2sinΦdΦdθ

Where da is the infinitesimal thickness of the surface.

Why am I getting the wrong answer?
 
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theBEAST said:

Homework Statement


I am currently trying to prove:

S = ∫∫a2sinΦdΦdθ

Here is my work (note that in my work I use dS instead of S, this is an accident):
Handwritten derivation of a spherical shell volume integral in spherical coordinates, with a small sphere diagram showing the dV and dS patch, ending with a comparison to a formula from notes.


I end up with:

S = ∫∫a*da2sinΦdΦdθ

Where da is the infinitesimal thickness of the surface.

Why am I getting the wrong answer?

You haven't computed S. You've computed the volume V=S*da. To get S, divide by the da.
 
Dick said:
You haven't computed S. You've computed the volume V=S*da. To get S, divide by the da.

I thought that if the volumetric shell thickness approaches zero you end up with the surface area?
 
theBEAST said:
I thought that if the volumetric shell thickness approaches zero you end up with the surface area?

If the shell thickness approaches zero then you end up with zero volume. To get the surface area divide by the thickness as it approaches zero. Maybe that's what 'volumetric shell' means.
 
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