Path integral and partition function

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The discussion centers on the relationship between transition amplitudes, partition functions, and functional determinants in quantum field theory, specifically referencing Peskin's textbook. The transition amplitude involving time evolution is compared to the partition function and functional determinant, with the participant noting that while the partition function and functional determinant appear equivalent, the transition amplitude requires clarification. It is suggested that imposing periodic boundary conditions on the transition amplitude could align it with the partition function, but this leads to confusion about the right-hand sides of the equations. Ultimately, it is concluded that the left-hand side of the transition amplitude is a specific case of the partition function, focusing on a single initial wavefunction rather than a combination. This highlights the nuanced relationship between these concepts in quantum mechanics.
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I have some confusions identifying the following objects:
(1)Some transition amplitude involving time evolution(Peskin page 281, eqn 9.14):
\langle\phi_b(\mathbf x)|e^{-iHT}|\phi_a(\mathbf x)\rangle=\int{\cal D\phi \;exp[i\int d^4x\cal L]}
(2)Partition function(after wick rotation)
Z_0=Tr(e^{-\beta H})=\int{\cal D\phi \;exp[i\int d^4x\cal L]}
(3)Functional determinant(Klein-Gordon for example, Peskin page 287, eqn 9.25)
const\times [det(\partial^2+m^2)]^{-\frac{1}{2}}=\int{\cal D\phi \;exp[i\int d^4x\cal L]}
All three appear in chap 9 of Peskin's textbook. though (2) is not explicitly written.
I can convince myself (2) and (3) are the same, but have trouble with (1). To make LHS of (1) the same with LHS of (2), shouldn't we impose periodic boundary condition on (1) and integrate over all initial states? That is,
\int{\cal D}\phi_a\langle\phi_a(\mathbf x)|e^{-iHT}|\phi_a(\mathbf x)\rangle=\int{\cal D}\phi_a\int{\cal D\phi \;exp[i\int d^4x\cal L]}
But then the RHS of (1) and (2) become different.
 
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No, the right-hand sides of (1) and (2) are still the same. The left-hand side of (1) is just a special case of the left-hand side of (2), where the initial state is a single wavefunction, rather than a linear combination of many wavefunctions. In this case, the integration over all possible initial states can be simplified to a single integration over the initial wavefunction.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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