Path of Light Through a Circular Raindrop

[Tasha9000]

Path of Light Through a Circular (Spherical) Raindrop

Homework Statement

I need to draw an accurate diagram of a light ray's path through a circular raindrop.
-The angle of incidence is 25degrees.
-The radius is 4.15cm
-n of water is ~1.33
-n of air is ~1.000293

I can calculate the first angle of refraction, but I cannot calculate the angle at which the light ray reflects from the raindrop. It does not say how in my textbook . Where is the normal?

Homework Equations

Snell's Law
n_AsinA=n_BsinB

The Attempt at a Solution

https://www.physicsforums.com/attachment.php?attachmentid=23940&d=1267138827g

angle of refraction:

B=sin^-1((1.000293sin(25degrees))/1.33)=18.533

 

[Tasha9000]

Can somebody please help?

 

[Tasha9000]

Is this right or completely wrong?
https://www.physicsforums.com/attachment.php?attachmentid=23944&d=1267153824
(except with the arrows pointing the correct way)

 

[ideasrule]

This is a sphere, so the normal at any point is the line that passes through the point, through the center, and straight to the other side.

 

[Tasha9000]

Thanks!
I'm going to guess this is the correct answer:

 

[Redbelly98]

Looks right to me. Do they want you to calculate any of the distances in the figure, or is just getting the angles good enough?