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Path of Light Through a Circular Raindrop

  1. Feb 25, 2010 #1
    Path of Light Through a Circular (Spherical) Raindrop

    1. The problem statement, all variables and given/known data

    I need to draw an accurate diagram of a light ray's path through a circular raindrop.
    -The angle of incidence is 25degrees.
    -The radius is 4.15cm
    -n of water is ~1.33
    -n of air is ~1.000293

    I can calculate the first angle of refraction, but I cannot calculate the angle at which the light ray reflects from the raindrop. It does not say how in my textbook :frown:. Where is the normal?

    2. Relevant equations

    Snell's Law
    nAsinA=nBsinB

    3. The attempt at a solution

    https://www.physicsforums.com/attachment.php?attachmentid=23940&d=1267138827g

    angle of refraction:

    B=sin-1((1.000293sin(25degrees))/1.33)=18.533
     
    Last edited: Feb 25, 2010
  2. jcsd
  3. Feb 25, 2010 #2
    Can somebody please help?:frown:
     
  4. Feb 25, 2010 #3
    Is this right or completely wrong?
    https://www.physicsforums.com/attachment.php?attachmentid=23944&d=1267153824
    (except with the arrows pointing the correct way)
     
  5. Feb 25, 2010 #4

    ideasrule

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    Homework Helper

    This is a sphere, so the normal at any point is the line that passes through the point, through the center, and straight to the other side.
     
  6. Feb 25, 2010 #5
    Thanks!
    I'm going to guess this is the correct answer:
     

    Attached Files:

  7. Feb 26, 2010 #6

    Redbelly98

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    Staff Emeritus
    Science Advisor
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    Looks right to me. Do they want you to calculate any of the distances in the figure, or is just getting the angles good enough?
     
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