PDE: a traveling wave solution to the diffusion equation

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SUMMARY

The discussion focuses on the traveling wave solution to the diffusion equation and the wave equation. It establishes that for a traveling wave of the form u(x,t) = f(x - at) to be a solution of the wave equation, the speed must be a = ±c, unless f is a linear function. In contrast, for the diffusion equation, the speed a is arbitrary, and the function f can be derived by substituting u(x,t) into the diffusion equation, leading to a simple ordinary differential equation (ODE) for f'.

PREREQUISITES
  • Understanding of wave equations, specifically u_{tt} = c^2u_{xx}
  • Knowledge of diffusion equations, particularly u_{t} = ku_{xx}
  • Familiarity with integral transforms, such as the Gaussian integral in the diffusion equation
  • Basic differential equations, including the ability to solve ODEs
NEXT STEPS
  • Study the derivation of solutions for the wave equation using Fourier transforms
  • Learn about the properties of Gaussian functions and their applications in diffusion problems
  • Investigate the method of characteristics for solving partial differential equations
  • Explore the implications of linear versus nonlinear functions in wave and diffusion contexts
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Students and professionals in applied mathematics, physics, and engineering who are working with partial differential equations, particularly those interested in wave and diffusion phenomena.

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Homework Statement



Consider a traveling wave u(x,t) =f(x - at) where f is a given function of one variable.
(a) If it is a solution of the wave equation, show that the speed must be a = \pm c (unless f is a linear function).
(b) If it is a solution of the diffusion equation, find f and show that the speed a is arbitrary.

Homework Equations



Wave: u(x,t) = f(x+ct) + g(x-ct) and u_{tt} = c^2u_{xx}

Diffusion: u_{t} = ku_{xx} and u(x,t) = \frac{1}{\sqrt{4kt\pi}}\int^{\infty}_{-\infty}e^{-(x-y)^2/4kt}\phi(y)dy

The Attempt at a Solution



(a) The wave equation is u_{tt} = c^2u_{xx} with the general solutions u(x,t) = f(x + ct) + g(x - ct), so for the solution to be u(x,t) = f(x-at), a = \pm c. If f is linear, then u_{tt} =u_{xx}=0, so it doesn't matter what a equals.

(b) u(x,t) = f(x-at) = \frac{1}{\sqrt{4kt\pi}}\int^{\infty}_{-\infty}e^{-(x-y)^2/4kt}\phi(y)dy I don't know where to go from here.
 
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Plug f(x-at) into the diffusion equation. You will get a simple ODE for f', from which you can obtain all the possible f so that f(x-at) satisfies the PDE.
 

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