PDE Heat Equation 2 Dimensions

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SUMMARY

The discussion centers on demonstrating that if v(x,t) and w(y,t) are solutions to the 1-dimensional heat equation (v_t = k*v_xx and w_t = k*w_yy), then the function u(x,y,t) = v(x,t)w(y,t) satisfies the 2-dimensional heat equation u_t = k(u_xx + u_yy). Participants emphasize the importance of correctly substituting the product function into the heat equation to verify the solution. Additionally, the conversation touches on the potential for generalization to three dimensions and the relevance of boundary conditions, specifically homogeneous Dirichlet boundary conditions, in solving partial differential equations (PDEs).

PREREQUISITES
  • Understanding of the 1-dimensional heat equation (v_t = k*v_xx)
  • Familiarity with the 2-dimensional heat equation (u_t = k(u_xx + u_yy))
  • Knowledge of boundary conditions, particularly homogeneous Dirichlet boundary conditions
  • Basic concepts of separation of variables in PDEs
NEXT STEPS
  • Study the derivation of the 2-dimensional heat equation from the 1-dimensional case
  • Explore the application of homogeneous Dirichlet boundary conditions in PDEs
  • Investigate the generalization of the heat equation to three dimensions
  • Learn about the method of separation of variables for solving PDEs
USEFUL FOR

Students and educators in mathematics, particularly those focused on partial differential equations, as well as researchers and professionals working with heat transfer and diffusion processes.

RJLiberator
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Homework Statement


Show that if v(x,t) and w(y,t) are solutions of the 1-dimensional heat equation (v_t = k*v_xx and w_t = k*w_yy), then u(x,y,t) = v(x,t)w(y,t) satisfies the 2-dimensional heat equation. Can you generalize to 3 dimensions? Is the same result true for solutions of the wave equation?

Homework Equations

The Attempt at a Solution



Honestly, I have no idea what I am doing. This is all very interesting and it SEEMS like it should be answered by a "oh, yes, that's obvious just do this" quick few lines.

But I'm so foreign with my PDE course that this is causing great stress.

I need a start, if you can tell me what I should look at, or where I should start, please do so. I will attack it then.
 
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RJLiberator said:

Homework Statement


Show that if v(x,t) and w(y,t) are solutions of the 1-dimensional heat equation (v_t = k*v_xx and w_t = k*w_yy), then u(x,y,t) = v(x,t)w(y,t) satisfies the 2-dimensional heat equation. Can you generalize to 3 dimensions? Is the same result true for solutions of the wave equation?

Homework Equations

The Attempt at a Solution



Honestly, I have no idea what I am doing. This is all very interesting and it SEEMS like it should be answered by a "oh, yes, that's obvious just do this" quick few lines.

But I'm so foreign with my PDE course that this is causing great stress.

I need a start, if you can tell me what I should look at, or where I should start, please do so. I will attack it then.

Step 1: write down the 2D heat equation for a general function u(x,y,t).
Step 2: plug in the suggested form for u(x,y,t) to see if it "works".
 
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I agree with your method and can see that this problem isn't that hard... once you understand the heat equation.

I am searching now for more information on the 2D heat equation.
 
A good starting point?

Homogeneous Dirichlet B.C.:

Screen Shot 2016-03-10 at 9.00.43 PM.png
 
RJLiberator said:
A good starting point?

Homogeneous Dirichlet B.C.:

View attachment 97157

Not much of a start I'd say. A better start would be to write down what you are given, then write down what you are to prove. Then you could start working on it...
 
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@LCKurtz ,

I have an extension on this assignment.

I am going to go through some intense studying tonight and I will report back with my updated tries for this problem and the other PDE problem I posted.

Thank you for your guidance thus far! Hopefully I come through.
 
@Ray Vickson
The 2D heat equation I am wondering what this means.

I have the 1d heat equation as follows:
u_t =k∇^2u
u(x,t) = k*∇^2u

is the 2d heat equation just
u(x,y,t) = k*(uxx+kuyy)

?

Separation of variable yiels
T'/(K*T) = X''/X = Y''/Y = -v^2
 
Last edited:
RJLiberator said:
@Ray Vickson
The 2D heat equation I am wondering what this means.

I have the 1d heat equation as follows:
u_t =k∇^2u
u(x,t) = k*∇^2u

is the 2d heat equation just
u(x,y,t) = k*(uxx+kuyy)

?

You mean ##u_t = k(u_{xx}+u_{yy})##, but, yes, that is what it means.

Separation of variable yiels
T'/(K*T) = X''/X = Y''/Y = -v^2

This problem has nothing to do with separation of variables. Start by following my advice in post #5.
 
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Okay, what do we know?

Well, we know the 2 dimension heat equation now:
u(x,y,t) = k(U_xx+U_yy)
we know u(x,y,t) = v(x,t)w(y,t) from problem description.

we know
V_t = k*V_xx and w_t=k*w_yy

Do we set:
v(x,t)w(y,t) = k(U_xx+U_yy)

The thing that is confusing me is the left hand side, how do I work with a function of this nature.
 
  • #10
It is very bad form, not to mention confusing, when you use both u and U and v and V to represent the same thing as you have done below. Don't do that.

RJLiberator said:
Okay, what do we know?

Well, we know the 2 dimension heat equation now:
u(x,y,t) = k(U_xx+U_yy)
we know u(x,y,t) = v(x,t)w(y,t) from problem description.

I wouldn't call that u(x,y,t) because it suggests it is the same u in the heat equation. Call it something new like$$F(x,y,t) = v(x,t)w(y,t)$$
The question is whether or not ##F(x,y,t)## satisfies the heat equation ##u_t = k(u_{xx} + u_{yy})##.

we know
V_t = k*V_xx and w_t=k*w_yy

Do we set:
v(x,t)w(y,t) = k(U_xx+U_yy)
No. You plug ##F(x,y,t)## into the heat equation and see if what you are given makes it work.
 
Last edited:
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