PDE: Initial Conditions Contradicting Boundary Conditions

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SUMMARY

The discussion centers on the initial boundary value problem (IBVP) for the partial differential equation (PDE) defined as \( u_{t} = \alpha^{2} u_{xx} \) with boundary conditions (BCs) \( u(0,t) = 0 \) and \( u_{x}(1,t) = 1 \), and initial condition (IC) \( u(x,0) = \sin(\pi x) \). The inconsistency arises from the derivative at \( x=1 \) being constant at 1, while the initial condition suggests a derivative of -π. The resolution involves using the substitution \( u(x,t) = v(x,t) + \psi(x) \) to transform the problem into a homogeneous system for \( v(x,t) \), allowing \( \psi(x) \) to address the non-homogeneous term \( u_{x}(1,t) = 1 \).

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Arkuski
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Suppose we have the following IBVP:

PDE: u_{t}=α^{2}u_{xx} 0<x<1 0<t<∞
BCs: u(0,t)=0, u_{x}(1,t)=1 0<t<∞
IC: u(x,0)=sin(πx) 0≤x≤1

It appears as though the BCs and the IC do not match. The derivative of temperature with respect to x at position x=1 is a constant 1 while with the initial condition, the derivative is equal to -π. Do I conclude that the problem is incorrect or is there another way to reconcile this error?
 
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I don't think there is an error. You can think of a bar with the given temperature distribution inserted into a situation with those bc's. I would begin by using a substitution like ##u(x,t) = v(x,t)+\psi(x)## to make a homogeneous system in ##v(x,t)## and let the ##\psi(x)## take care of the ##u_x(1,t)=1## nonhomogeneous term.
 

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