- #1

- 25

- 0

I have a simple question (assuming since it was only worth 5% of total marks in the exam) about the

**random variable**.

Given that PDF of random signal equals p(X) = [tex]\Lambda[/tex](X), where [tex]\Lambda[/tex] is the triangle function, what would be the PDF of the random signal Y, Y = -3X + 2.

That was the question given, and I've given it a lot of thought but I cannot come up with any way to solve it.

What I did in the exam was:

p(Y) = [tex]\Lambda[/tex](Y) = [tex]\Lambda[/tex](-3X + 2) but this looks sooo wrong. Basically I have no idea what I'm doing on this question.

Can somebody kindly guide me, preferrably by presenting all the steps so that I can understand and apply to future problems.

Thank you very much for your time and consideration.