A 5 kg sphere is connected to a thin
massless, but rigid rod of length L = 1.3 m to
form a simple pendulum. The rod is connected
to a nearby vertical wall by a spring with spring
constant k = 75 N/m, connected to it at a
distance h = 1.1 m below its point of
suspension. What is the angular frequency (in
rad/s) of the system for small amplitude
The Attempt at a Solution
So I was listening to my teacher start to solve this problem. He starting talking about summing the torques between these two. I have the equation he wrote down from it, but I am not too sure what to do with it... ([tex]\tau[/tex])net = -Lmgsin[tex]\theta[/tex] - hk[tex]\Delta[/tex]xsin[tex]\beta[/tex] = m(l^2)[tex]\alpha[/tex]
Note: alpha is not a power...
I know that the small angle theorum makes sin go away. But how is beta and alpha related? And what about delta x? I don't know I've been working on it for a while and now I'm tired. Thanks for helping!