A simple pendulum, 2.0 m in length, is released by a push when the support string is at an angle of 25° from the vertical. If the initial speed of the suspended mass is 1.2 m/s when at the release point, to what maximum angle will it move in the second half of its swing? Let h1 be the elevation reached when potential energy = total energy transferred. mg(h1) = mgL(1 - cos θ0) + 1/2 (mV²) I am not sure if the approach is correct and how to proceed. My trig. background is not that strong at all. Please help. I believe the answer is 30 degrees.