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Pendulum Motion (Simple Harmonic Motion)
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[QUOTE="John Park, post: 5707892, member: 616032"] It would be best to work with 3 significant figures everywhere (0.12 rad isn't particularly accurate). You write: theta(t) = A * cos(omega * t + phi) But theta is an angle and A is a distance in metres. . . . It's the [I]angular[/I] displacement that behaves simple-harmonically (i.e. varies sinusoidally)--there's usually no need to convert to a linear distance. In fact you could leave those angles in degrees; mathematically, degrees make as much sense as metres in this context, and they save work. (Perhaps a simpler way to think about this part: What is the period of the motion? What fraction of that period is the time taken for the mass to swing from the extreme to the centre? --Think about what a sine or cosine curve looks like and what sorts of symmetry it has.) For the second part, I think you're making it a bit more complicated than it needs to be. Remember the mass is in continuous sinusoidal motion from the time it's released. [/QUOTE]
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Pendulum Motion (Simple Harmonic Motion)
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