Pendulum of unknown length and unknown g, only period given

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SUMMARY

The discussion centers on calculating the original length of a pendulum with an unknown length, l, and gravitational acceleration, g, given a period of 9.32 seconds and an increased length resulting in a period of 9.734 seconds. The relevant equation for the period of a pendulum is T = 2π√(l/g). By setting up two equations based on the provided periods and lengths, users can solve for both l and g, determining whether the experiment was conducted on Earth.

PREREQUISITES
  • Understanding of pendulum motion and periodicity
  • Familiarity with algebraic manipulation of equations
  • Knowledge of gravitational acceleration concepts
  • Basic trigonometry for understanding periodic functions
NEXT STEPS
  • Study the derivation of the pendulum period formula T = 2π√(l/g)
  • Explore methods for solving systems of equations with two variables
  • Investigate variations in gravitational acceleration in different environments
  • Learn about the impact of pendulum length on oscillation periods
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Students in physics, educators teaching mechanics, and anyone interested in the mathematical modeling of pendulum motion.

mh1985
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Homework Statement



Pendulum of unknown length, l, has period of 9.32 seconds. Length is increased by 1 metre, and time period increases to 9.734 seconds. Calculate original length of pendulum and determine whether the experiment was conducted on earth. Hint: g is not assumed to be 9.81 ms^-2, you must find both g & l

Homework Equations



x(t) = A1 cos vnt + A2 sin vnt?

The Attempt at a Solution



Really not sure where to start, due to the two unknowns!
 
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Can you express the period as function of g and l?
For both pendulum lengths, you get an equation, so you have two unknowns and two equations.
 
mfb said:
Can you express the period as function of g and l?
For both pendulum lengths, you get an equation, so you have two unknowns and two equations.

T=2pi(sqrt(l/g) ?
 
That is right, and it will help you.
 

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