- #1

Ethxn

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Member advised to use the homework template for posts in the homework sections of PF.

To increase the period of oscillation of a pendulum in 1 second, it is needed to increase the length of it in 2 meters. Calculate, in seconds, of the initial period of oscillation of the pendulum.

I found this question online a few minutes ago. I have not learned this in physics class yet so bare with me :)

Because it is asking for the period of the oscillation I figured I would need the equation: T = 2π√(l/g)

To set up the equation, I wrote it like this

2π√(l/g) + 1 = 2π√(l+2/g)

as the period of the oscillation increased by one when the length increased by 2 meters. When I solve this equation though, everything except cancels itself out, so I can't find the initial length to plug back into the equation to find the initial period... Again, I am 1 month in of my first year of physics so don't crucify me for my mistakes please (lol), and the wording on this question is quite confusing too, so I may have it all wrong but hopefully you can see where I'm going with this ;)

Thanks in advance!

I found this question online a few minutes ago. I have not learned this in physics class yet so bare with me :)

Because it is asking for the period of the oscillation I figured I would need the equation: T = 2π√(l/g)

To set up the equation, I wrote it like this

2π√(l/g) + 1 = 2π√(l+2/g)

as the period of the oscillation increased by one when the length increased by 2 meters. When I solve this equation though, everything except cancels itself out, so I can't find the initial length to plug back into the equation to find the initial period... Again, I am 1 month in of my first year of physics so don't crucify me for my mistakes please (lol), and the wording on this question is quite confusing too, so I may have it all wrong but hopefully you can see where I'm going with this ;)

Thanks in advance!