Pendulum Problem and steiner' law

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SUMMARY

The discussion centers on calculating the period of a physical pendulum, specifically a uniform circular disk with a radius of 14.3 cm. The period was correctly determined to be 0.849 seconds using the formula T = 2π√(I/mgh). For part B, participants are advised to apply Steiner's law to express the moment of inertia (I) through a parallel axis and equate the period of the disk to that of a simple pendulum to find the radial distance.

PREREQUISITES
  • Understanding of physical pendulum dynamics
  • Familiarity with the formula T = 2π√(I/mgh)
  • Knowledge of Steiner's law for moment of inertia
  • Basic concepts of simple pendulum motion
NEXT STEPS
  • Study the application of Steiner's law in rotational dynamics
  • Research methods to derive the moment of inertia for various shapes
  • Learn about the relationship between period and pivot points in pendulum systems
  • Explore the derivation of the period for simple pendulums
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and pendulum motion, as well as educators seeking to enhance their understanding of rotational dynamics and moment of inertia calculations.

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Homework Statement


A uniform circular disk whose radius R is 14.3 cm is suspended as a physical pendulum from a point on its rim. (a) What is its period? (b) At what radial distance r < R is there a pivot point that gives the same period? (give answer in cm)

Homework Equations


T= 2pi radical ( I / mgh )

The Attempt at a Solution


Okay, I already found part A using T= 2pi radical ( I / mgh )
Any help would be greatly appreciated =]

Part A: 0.849 s <-- It's correct.
I'm just stuck on Part B.
 
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Use steiner' law to express the I through a parallel axis..
 
You can find the radial distance by equating period of the disk to that of a simple pendulum.
 

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