- #1

Clearik

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## Homework Statement

A pendulum is composed of a thin rod of length L = 50 cm, a moment of inertia of I = 0.2kgm

^{2}with respect to its center and mass M = 400g. Attached to the bottom of the rod is a point mass (m = 200g). The pendulum swings in a vertical plane, attached by the top end to the ceiling.

## Homework Equations

T = 2∏√(I/Mg x d)

*I think*

## The Attempt at a Solution

T = 2∏√(.2/(.4)(10) x .25)

No radius was given for the point mass, so I assumed the moment of inertia of center of mass is .2kgm

^{2}and therefore the distance of center of mass (d) would be L/2 or .25m

Did I go about solving this correctly?

Also, the second problem asks: How long will it take for the pendulum to perform 100 oscillations?

Would I simply multiple the period I found from the first part by 100?

Thank you all for your time and consideration.

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