Penetration depth of a microwave

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SUMMARY

The penetration depth of microwave waves is determined by the square root of the dielectric constant divided by the dielectric loss, as confirmed by sources such as LSBU. An increase in dielectric loss results in a smaller penetration depth due to more energy being converted into heat. Conversely, a higher dielectric constant leads to increased penetration depth, indicating that while electromagnetic energy is absorbed, it may not necessarily be converted into heat. The complex permittivity, comprising real and imaginary components, plays a crucial role in energy dissipation, with the imaginary part accounting for energy loss.

PREREQUISITES
  • Understanding of dielectric materials and their properties
  • Familiarity with microwave physics and electromagnetic theory
  • Knowledge of complex permittivity and its components
  • Basic principles of energy absorption and heat transfer
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  • Research the relationship between dielectric constant and microwave penetration depth
  • Explore the concept of complex permittivity in detail
  • Investigate materials with high dielectric constants and low dielectric losses
  • Learn about energy dissipation mechanisms in dielectric materials
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PTlusitano1143
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Hi,

according to http://www1.lsbu.ac.uk/water/microwave_water.html and other sources the penetration depth of a microwave wave is proportional to the square root of the dielectric constant divided by the dielectric loss. For me it makes sense that as the dielectric loss increases more energy is being converted into heat and penetration depth is smaller but why does the penetration depth increases with an increase in the dielectric constant if more electromagnetic energy is being absorbed by the medium?

also, another question, what is the physical meaning of a material that has a high dielectric constant and low dielectric loss? what is happening to all the energy that is being absorbed if it is not being released as heat?

thank you for your replies
 
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PTlusitano1143 said:
what is happening to all the energy that is being absorbed if it is not being released as heat?
Absorbed energy has to be transferred as heat but the field can be reduced without dissipation - it is just redirected back out. The complex permittivity has a real and imaginary part and it is the imaginary part that is responsible for energy loss.
 

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