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We use, among others, Penning pressure gauges for determining pressures (aprox. 1E-7 to 1 mbar (about the same in Torr... for the Americans here ;-) ).
The Penning is placed just outside the recipient, behind a valve to make sure its never in pressures of 1mbar or more.
When using a smaller valve, the measured end pressure is higher (entrapped particles probably?). But the question now is, how to pre-determine how much higher the measured pressure will be due to this effect, without having to measure for each application.
My feeling is that a smaller valve and therefore smaller pipes in front of the gauge, result in relatively more particles being entrapped in the volume of the gauge. But I can't find a good way of approximating the effect.
More general:
* What is the effect a decreased diameter in front of the measurement?
Any thoughts are welcome!
Ryyder
The Penning is placed just outside the recipient, behind a valve to make sure its never in pressures of 1mbar or more.
When using a smaller valve, the measured end pressure is higher (entrapped particles probably?). But the question now is, how to pre-determine how much higher the measured pressure will be due to this effect, without having to measure for each application.
My feeling is that a smaller valve and therefore smaller pipes in front of the gauge, result in relatively more particles being entrapped in the volume of the gauge. But I can't find a good way of approximating the effect.
More general:
* What is the effect a decreased diameter in front of the measurement?
Any thoughts are welcome!
Ryyder
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