Percent change in tension to achieve specified change in frequency

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SUMMARY

The discussion centers on calculating the percentage change in tension required to adjust the frequency of a guitar string from 224 Hz to the desired 219 Hz. The formula used is derived from the wave equation, specifically v=f(λ)=√(tension/μ), leading to the relationship (T1/T2) = (F1/F2)². The calculated percentage change in tension is 4.41%. However, the initial approach was flawed due to the incorrect application of the formula, specifically neglecting the necessity of a negative sign to indicate a decrease in tension.

PREREQUISITES
  • Understanding of wave mechanics and frequency
  • Familiarity with the guitar string tension formula v=f(λ)=√(tension/μ)
  • Basic algebra for manipulating equations
  • Knowledge of percentage calculations
NEXT STEPS
  • Review the principles of wave mechanics in string instruments
  • Study the derivation and application of the wave equation v=f(λ)=√(tension/μ)
  • Practice solving problems involving frequency and tension changes in strings
  • Explore the effects of tension on pitch in stringed instruments
USEFUL FOR

Musicians, physics students, and anyone interested in the mechanics of string instruments and frequency adjustments will benefit from this discussion.

Jennifer_ea
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% change in tension to achieve specified change in frequency

Homework Statement


A particular guitar string is supposed to vibrate at 219 Hz, but it is measured to actually vibrate at 224 Hz. By what percentage should the tension in the string be changed to get the frequency to the correct value?

Homework Equations


v=f(lambda)=sqrt(tension/mu)

Rearranged and combined to give:
(T1/T2) = (F1/F2)^2

The Attempt at a Solution


This seemed like it should be a very simple problem, I must be doing something basic wrong.

Subbing in the values and changing for %:
%change in Tension = 100 * [1 - (219/224)^2]
= 4.41

However this is shown wrong by the system. I also tried putting in 0.0441 just incase, but no dice. I can't think of any other way to approach this.

Thanks for any help you can give!
 
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Welcome to PF!

Hi Jennifer_ea! Welcome to PF! :smile:

(have a lambda: λ and a mu: µ and a square-root: √ and try using the X2 tag just above the Reply box :wink:)
Jennifer_ea said:
v=f(lambda)=sqrt(tension/mu)

Subbing in the values and changing for %:
%change in Tension = 100 * [1 - (219/224)^2]
= 4.41

Why the "1 - " ? :wink:
 


Oops, didn't notice that option!

Yup, I knew this would be a face palmer. When doing the logic out I knew it had to decrease but somehow deemed the negative unwarranted.

Thanks a million!
 

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