You record the following data Diameter/mm: 11.67, 12.67, 13.9, 12.67, 12.67, 12.66 You take the average of these values to be the diameter, but what is the percentage error in this value?(adsbygoogle = window.adsbygoogle || []).push({});

I tried working this problem out but I cant use the normal formula as it is spread over many values and there is no accepted value. I got some numbers; 17.55%, 1.5% but theyr all wrong.

W = T(x+y)/x

Where W is the weight of the stand and T is the Newton meter reading.

You measure and record the values of x, y (with a ruler) and T. The following data is recorded:

x = 12.8 cm , y = 30.2 cm, T= 2.2 N

What is the percentage uncertainty in y?

This one wants the percentage uncertainty which I'm unsure of how to find. I did try 30.25(max value) - 30.15(lowest value) / 2 = 0.05 and find it as a percentage but it turned out to be wrong...

Any help with these problems would be much appreciated.

**Physics Forums - The Fusion of Science and Community**

# Percentage uncertainty and percentage error

Have something to add?

- Similar discussions for: Percentage uncertainty and percentage error

Loading...

**Physics Forums - The Fusion of Science and Community**