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**Question:**

If the temperature at both 9,000 ft and 0 ft (sea level) is 32 F, how much warmer would it feel at 9,000 ft due to the reduced thermal capacity of the air caused by lower air pressures?

**Available Facts:**

Air has 28.5% less pressure at 9,000 ft compared with sea level (0 ft). 10.5 psi vs 14.7 psi respectively.

**More Details:**

At sea level, a person who has a core temperature of 98.6 F who is standing in 32 F dry air would experience a relative temperature difference of 66.6 F. If this same person stood in 32 F dry air at 9,000 ft would he or she only experience a temperature difference of 47.5 F because of the reduced thermal capacity of the air?

**Calculations:**

0 ft = 98.6 F - 32 F = 66.6 F temperature difference

9,000ft = 66.6 F temperature difference * 71.45% air pressure difference = 47.5 F perceptive temperature difference

**Conclusion:**

If the above calculations are correct, would a person standing in 32 F dry air at 9,000 ft feel as if he or she is standing in 51 F dry air at sea level (98.6 F - 47.5 F) due to the reduced thermal capacity of the air?

Thank you very much,

Aquaflight