Percise defination of the limit of a sequence problem

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SUMMARY

The limit of the sequence defined by ln(n)/n as n approaches infinity is 0. To find a natural number N such that for all n > N, the inequality |ln(n)/n - 0| < 1/10 holds, one can set ε = 1/10. The solution involves determining N as a function of ε, specifically N = 10ln(n). The discussion highlights the challenge of expressing N purely in terms of ε while ensuring that ln(n) remains bounded above.

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Homework Statement



it is shown that lim n->Infinity of ln(n)/n=0
Find a natural number N such that
n> N -> |ln(n)/n - 0| < 1/10


The Attempt at a Solution



A sequence has a limit 0 if for every \epsilon>0 there exists a number N such that for every n > N

|ln(n)/n-0|<\epsilon

Take \epsilon=1/10, as ln(n)/n > 0 for any sufficently large n we have

ln(n)/n < 1/10.

so I choose N=10ln(n).

My problem starts here this is a function of a variable being sent to infinity I am not sure how exactly one solves for N that is purely a function of \epsilon.
 
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You can find any natural number, so just get an upper bound for ln(n).

For example, ln(n) < sqrt(n)
 

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