Period and angular frequency problem.

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SUMMARY

The discussion centers on the relationship between the period (T) of a simple harmonic motion and its angular frequency (ω). When the period decreases by 20%, the new period is 80% of the original, leading to the equation ω = 2π/T * (5/4). This calculation confirms that the angular frequency increases by 25%. Thus, a 20% reduction in period results in a 25% increase in angular frequency.

PREREQUISITES
  • Understanding of simple harmonic motion concepts
  • Familiarity with the relationship between period and angular frequency
  • Basic algebra for manipulating equations
  • Knowledge of trigonometric functions, specifically sine and cosine
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  • Study the derivation of angular frequency in simple harmonic motion
  • Learn about the effects of damping on period and frequency
  • Explore the relationship between frequency and energy in oscillatory systems
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Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators seeking to clarify concepts related to angular frequency and period in simple harmonic motion.

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Homework Statement



If period of simple harmonic graph of electric current goes down by 20%, how will change the angular frequency?
Will it increase by 25π%? 25%? 50%?...

Homework Equations



T = 2π/ω


The Attempt at a Solution



So by going down by 20%, so 100%-20%, I have 80%*T=2π/ω. 0.8*T=2π/ω. 8T/10=2π/ω. 4T/5=2π/ω. ω=2π/T *(5/4) = 2π/T * 1.25
So by this, angular frequency increases by 25%?
 
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