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## Homework Statement

A light wave has a frequency of 6 x 10

^{14}Hz. A) What is its period? B) What is its wavelength in a vacuum? C) When the light wave enters water, its velocity decreases to 0.75 times its velocity in vacuum. What happens to the frequency and wavelength?

## Homework Equations

c = λf

v = c/n

T = 1/f

## The Attempt at a Solution

I understood how to do parts A and B.

For A, since we know the frequency, we can take the equation for period, T to find the answer:

T = 1/f = 1/(6 x 10

^{14}Hz = 1.67 x 10

^{-15}sec.

For B, we know that c = 3.0 x 10

^{8}m/s in a vacuum and we're given the frequency so wavelength is found by taking the equation:

λ = c/f = (3.0 x 10

^{8}m/s)/(6 x 10

^{14}Hz) = 5 x 10

^{-7}m.

For part C, however, I got confused.

I believe we can use the equation:

v = c/n

We're told that velocity decreases by 0.75 times in a vacuum so I think that v then would be:

v = 0.75c

So from here, we have to relate it to the equation c = λf.

So would we use the equation:

0.75c = λf to find wavelength since we already what f is? Can we assume that f does not change but that wavelength would?

To get wavelength then, we'd take:

0.75c/f = λ?