Period of oscillation of spring system

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Homework Help Overview

The problem involves a system of two blocks, each with mass M, connected by a spring with force constant k. The system is initially compressed against a wall and released, with the goal of determining the period of oscillation once the left block is no longer in contact with the wall.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for the period of oscillation and question the concept of reduced mass in this context. There is uncertainty about the motion of the blocks after the left block leaves the wall, and some participants suggest visualizing the spring as divided into two halves to aid understanding.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the motion and the reasoning behind the period formula. Some guidance has been offered regarding the treatment of the spring and mass, but there is no consensus on the visualization of the motion.

Contextual Notes

Participants express difficulty in visualizing the motion after the initial release and question the assumptions made regarding the spring's behavior when not fixed to a wall.

SbCl3
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1. Question
A system consists of two blocks, each of mass M, connected by a spring of force constant k. The system is initially shoved against a wall so that the spring is compressed a distance D from its original uncompressed length. The floor is frictionless. The system is now released with no initial velocity. (See picture)

[part c] Determine the period of oscillation for the system when the left-hand block is no longer in contact with the wall.

Homework Equations



period = 2(pi)sqrt(m/k)

The Attempt at a Solution



The answer given is this: period = 2(pi)sqrt(M/(2k))
The explanation given is "m = reduced mass = M/2".

I don't understand the explanation given. I can't visualize what happens to the right mass M after the left mass M leaves the wall. This is different from all spring problems I have seen, where one end is attached to a wall, so of course I suspect a different answer. Could someone show me the math involved to prove the period is reduced like this?
 

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SbCl3 said:
The answer given is this: period = 2(pi)sqrt(M/(2k))
The explanation given is "m = reduced mass = M/2".

I don't understand the explanation given. I can't visualize what happens to the right mass M after the left mass M leaves the wall. This is different from all spring problems I have seen, where one end is attached to a wall, so of course I suspect a different answer. Could someone show me the math involved to prove the period is reduced like this?

Hi SbCl3! :smile:

Divide the spring into two halves, then you can consider each half to be fixed against a wall (in c.o.m. frame of reference, of course) … the spring constant is doubled (1/K = 1/k + 1/k), and the mass is M :wink:
 
Can anyone please describe the motion qualitatively? I cannot visualize this problem. After the blow, the spring is maximally compressed and the block on the right moves to the right, away from the wall. I know that the left mass leaves the wall the first time that the right mass has its maximum speed to the right and the spring is at its equilibrium length. But I have no idea how the motion is after that.

All help appreciated.
Thanks
 
Please help this question has been giving me nightmares.
 
does anyone have a link to an animation
 
guys?
 

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