Permutation problem: Seven friends queue up for a buffet....

  • Thread starter chwala
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  • #1
chwala
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Homework Statement:
solve the problem below;
Relevant Equations:
permutation and combination
1614052420899.png
 
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  • #2
chwala
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for the first part, not difficult,
we have ##7!=5040##
now for the second part, i get a bit confused here ok, i merged the last two fellows and now i have 6 items...
therefore i will have ##6C4 ##× the remaining ##3## can be arranged in 1 way only= ##15## is this the correct approach?...not one of my favorite topics o0)...

or can i say that, the car can be filled up in this way,
##5C2 ×1## way only(remaining 3 people), assuming that the two fellows board the 4-vehicle capacity or
##5C4 ×1 ##way only(2 fellows plus 1 person) , assuming that the two fellows board the vehicle holding 3 occupants...which gives
##10+5=15##
 
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  • #3
Delta2
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I agree with your solution.
 

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