1. The problem statement, all variables and given/known data 9 people, 2 cars can hold 5 people each. only 3 people have licenses. 2. Relevant equations How many different ways can the people be seated into cars? 3. The attempt at a solution There are nine people. So number of seats is not a problem. We must find out how many groups of three people with licenses there can be. nPr = n!(n-r)! n = 9 r = 3 nPr= 9!/(9-3)! = 504 How's that look?