(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

9 people, 2 cars can hold 5 people each. only 3 people have licenses.

2. Relevant equations

How many different ways can the people be seated into cars?

3. The attempt at a solution

There are nine people. So number of seats is not a problem.

We must find out how many groups of three people with licenses there can be.

nPr = n!(n-r)!

n = 9

r = 3

nPr= 9!/(9-3)! = 504

How's that look?

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# Permutations seat arrangements

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