Perpendicular 3D Vector Problem

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To find a vector perpendicular to [6,2,3] with the same length, one can utilize the concept that 3D vectors have infinite perpendiculars. The length of the vector can be calculated using the distance formula, but without a second point, determining the exact length is challenging. Starting from the origin can help visualize the problem, as the vector from the origin to [6,2,3] forms a triangle in 3D space. The discussion also touches on the scalar or dot product as a method to demonstrate perpendicularity between vectors. Understanding these concepts is essential for solving the problem effectively.
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Homework Statement


Give an example of a vector perpendicular to [6,2,3] that has the same length.

Homework Equations


Distance formula between two points on a 3D plane:
Sqrt[(X1-X2)2 + (Y1-Y2)2 + (Z1-Z2)2]

The Attempt at a Solution


In 2D space, the perpendicular vector of [X,Y] is [-Y,X]. However, I know that 3D vectors have an infinite number of perpendicular vectors. Then I thought to myself that I should use the distance between to points to figure out the length, but since the problem does not give me the second point, I do not know what the length of the line is. I was thinking of starting at the origin, since the line from the origin to the point is the hypotenuse of the triangle the points make in 3D. I got 6.2, but now do not know how to go from here. Help is very appreciated.

P.S. Just for further learning, how would I show that two vectors are perpendicular in the same equation?
 
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Have you learned about "scalar product" or "dot product" of two vectors?

ehild
 
No, not yet. Only a sophmore in high school. If those concepts A) are on the SAT and B) help me find the answer, an explanation would be very appreciated.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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