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Perpendicular components of the perpendicular plane

  1. Jun 30, 2012 #1
    What does the the cross product of two acceleration vectors do?

    (a cross ar) = 0

    where a =axi + ayj + azk and ar = arxi + aryj + arzk

    (a cross ar)x = ay*arz - az*ary
    (a cross ar)y = az*arx - ax*arz
    (a cross ar)z = ax*ary - ay*arx

    It gives the perpendicular components of each.

    In the perpendicular plane of "ar" what happens if you set the the cross product equal to an angle on that perpendicular plane.

    To give you control of which way the "ar" will execute:

    (a cross ar) = ap where ap = apxi +apyj + apzk

    ap is in the perpendicular plane of ar.
     
    Last edited: Jun 30, 2012
  2. jcsd
  3. Jul 1, 2012 #2
    What are you doing ? What's r ? Your question is vague and I cannot understand it. What do you mean by perpendicular plane ? Perpendicular to what ? A plane is a plane made of two independent coordinates !! Can you explain what are you doing exactly ?

    I think I gave you the reason why no one replied to your thread.
     
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