- #26

CAF123

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So then x(t) - x(t1) = ut -ut1 - 1/2(a + g)T^2 = u(T) - 1/2 (a+g)T^2Frankly, I am lost in all those terms. I would let vBH = u - (a + g)T, where T = t - t1, and integrate that. Then I would convert back to t and t1 if required.

It is not given so instead let x(t) - x(t1) = ΔxWhat is the value of x at t1, by the way?