Laws of motion and a projectile thrown from an accelerating elevator car

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Homework Help Overview

The discussion revolves around a projectile motion problem involving a ball thrown from an accelerating elevator. Participants explore the implications of different reference frames and the effects of acceleration on the ball's trajectory.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the initial velocities of the ball relative to the elevator and question the use of pseudo forces in different frames of reference. There is also exploration of whether the ball's trajectory can be considered horizontal from the perspective of the elevator.

Discussion Status

The conversation is ongoing, with participants sharing their reasoning and questioning assumptions about the problem setup. Some guidance has been offered regarding the use of reference frames, but no consensus has been reached on the correct approach or interpretation of the problem.

Contextual Notes

There is uncertainty regarding the definitions of horizontal motion in the context of the moving elevator and whether certain points of reference are fixed in space or relative to the elevator. Participants also note discrepancies between their calculations and the expected answers.

Prabs3257
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Homework Statement
An elevator car starts descending with constant acceleration 2 m/s2 2 seconds after the start a ball is thrown horizontally with 3 m/s with respect to elevator from point P then the magnitude of displacement of the ball with respect to the point P after 1 second is
Relevant Equations
Projectile eqns
At the moment of throwing the ball the ball will have a vertical vel of 4 and horizontal of 3 wrt to elevator so as seen from inside the elevator the ball will behave like a projectile where g(eff) = 8 and with time period 1 sec hence range will be the displacement which should be 3 m but ans given is 5 m please tell me where i am wrong
 

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I suggest you use an inertial reference frame where both the elevator and ball are moving.
 
PeroK said:
I suggest you use an inertial reference frame where both the elevator and ball are moving.
But wouldn't it be easier to solve it from inside the elevator and use pseudo force am i doing the projectile path correctly
 
Prabs3257 said:
But wouldn't it be easier to solve it from inside the elevator and use pseudo force am i doing the projectile path correctly

What does "horizontal" mean in this problem?
 
i guess it means that if seen from inside the elevator it seems as if the ball is thrown horizontally
 
Prabs3257 said:
i guess it means that if seen from inside the elevator it seems as if the ball is thrown horizontally
But, as the elevator and ball have different vertical accelerations that's not possible.
 
PeroK said:
But, as the elevator and ball have different vertical accelerations that's not possible.
but if we solve it from the elevator frame we can give that elevator's accel to the ball as pseudo force
 
Prabs3257 said:
but if we solve it from the elevator frame we can give that elevator's accel to the ball as pseudo force

Okay, so how did you get an answer of 3m?
 
so if we solve from the elevators frame ie make the elevator stationary the ball got a vertical vel of 4 and horizontal of 3 and by applying psudo force the net accel downward became 8 and time period came out to be 1 hence the displacement must be the range but my ans is not matching can you please tell me what i did wrong
 
  • #10
Prabs3257 said:
make the elevator stationary the ball got a vertical vel of 4
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.
 
  • #11
haruspex said:
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.

Working backwards, I guessed they meant horizontal in the (moving, inertial) frame of the elevator at the time the ball was projected.

Prabs3257 said:
so if we solve from the elevators frame ie make the elevator stationary the ball got a vertical vel of 4 and horizontal of 3 and by applying psudo force the net accel downward became 8 and time period came out to be 1 hence the displacement must be the range but my ans is not matching can you please tell me what i did wrong

There shouldn't be an initial vertical velocity of ##4m/s##. That would be a horizontal trajectory relative to the ground; not the elevator.
 
  • #12
haruspex said:
It says the ball is thrown horizontally relative to the elevator.
But it's not quite clear to me whether P is fixed in space or fixed to the elevator. You'd think it was fixed in space, but then I don't get any of the given answers.
i got my ans by considering that p is in the elevator
 
  • #13
PeroK said:
Working backwards, I guessed they meant horizontal in the (moving, inertial) frame of the elevator at the time the ball was projected.
Yes, that's what I wrote. My uncertainty concerns P.
 
  • #14
Prabs3257 said:
i got my ans by considering that p is in the elevator
Ok, so do that, but take the ball as being thrown horizontally relative to the instantaneous motion of the elevator.
 

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