Perturbation from a quantum harmonic oscillator potential

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SUMMARY

The discussion focuses on calculating the Hmn terms in the context of perturbation theory for a quantum harmonic oscillator. It highlights the challenges posed by the off-diagonal term (pq + qp) due to the complexity of the wavefunctions. The use of creation and annihilation operators is suggested as a method to simplify the computation. Additionally, the user explores an analytical approach by redefining momentum and position operators, leading to a new Hamiltonian expression involving these transformed operators.

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  • Quantum mechanics fundamentals
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Mayan Fung
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Homework Statement
Given the hamiltonian ##\hat{H}##:
$$\hat{H} = \frac{\hat{p}^2}{2} + \frac{\hat{q}^2}{2} + \alpha (\hat{p}\hat{q}+\hat{q}\hat{p})$$

Approximate the eigenvectors and eigenvalues numerically using the known eigenvectors with ##\alpha = 0## (That means I am asked to truncate the infinitely large matrix and find the eigenvectors and eigenvalues of the truncated matrix)
Relevant Equations
$$ E = \hbar \omega (n+\frac{1}{2}) $$
For the off-diagonal term, it is obvious that (p^2+q^2) returns 0 in the integration (##<m|p^2+q^2|n> = E<m|n> = 0##). However, (pq+qp) seems to give a complicated expression because of the complicated wavefunctions of a quantum harmonic oscillator. I wonder whether there is a good method to compute the Hmn terms?
 
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Try using the creation and annihilation operators.
 
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Likes   Reactions: hutchphd, Abhishek11235 and Mayan Fung
vela said:
Try using the creation and annihilation operators.

Thanks! It helps a lot.

I also tried to solve it analytically by substituting:
$$\hat{p'} = \hat{p} + \hat{q}$$
$$\hat{q'} = \hat{p} - \hat{q}$$
I finally got something like ##\hat{H} = a\hat{p'} + b\hat{q'} ##

However, ##p',q'## are composed of both p and q. How I can get the wavefunction in the q space?
 

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