Peskin Schroeder: How to Derive Sin^2 Using Compton Relation?

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Dear PF,

I have one question form Peskin Schroeder...could you pls help me
It is very simple question...
Since I don't know how to write formulas here I put my question in attachment.

Thank you very much.
 

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Well just use the fact that [itex]pk=m\omega[/itex] and [itex]pk'=m\omega'[/itex] plus the Compton relation

[tex]\frac{1}{\omega}-\frac{1}{\omega'}=\frac{\cos\theta - 1}{m}[/tex]

And you'll get that -sin^2 after using a bit of trigonometry.