PH, Alkalinity, and total carbonate concentration

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SUMMARY

The discussion focuses on calculating alkalinity and total carbonate concentration in natural water with a pH of 7.8 and an alkalinity of 125 meq/L. The alkalinity was successfully converted to 6250 mg/L of CaCO3 using the equivalent weight of CaCO3 (50 g/eq). The total carbonate concentration (CT) was approximated to be 0.125 moles per liter. The relationship between alkalinity and carbonate concentration is established through a quantitative formula that includes bicarbonate, carbonate, hydroxide, and hydrogen ions.

PREREQUISITES
  • Understanding of alkalinity and its measurement in water chemistry
  • Knowledge of equivalent weights and their application in calculations
  • Familiarity with carbonate species: HCO3-, CO32-, and their roles in buffering
  • Basic grasp of pH, pOH, and their relationship in aqueous solutions
NEXT STEPS
  • Study the calculation of alkalinity using the formula: Alkalinity = (1 eq/mol)([HCO3]) + (2 eq/mol)([CO3]) + (1 eq/mol)([OH]) - (1 eq/mol)([H])
  • Learn about the influence of carbonic acid (H2CO3) on alkalinity and carbonate concentration
  • Explore the impact of pH on the speciation of carbonate species in natural waters
  • Investigate methods for measuring total carbonate concentration in water samples
USEFUL FOR

Environmental scientists, water quality analysts, and students studying aquatic chemistry will benefit from this discussion, particularly those focused on alkalinity and carbonate dynamics in natural water systems.

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Homework Statement


If the pH of a natural water is 7.8 and the alkalinity was measured to be 125 meq/L, determine the following:
-Alkalinity as mg/L CaCO3: Answer = 6250 mg/l CaCO3
-Approximate the total carbonate concentration CT, in moles per liter: Answer = 0.125 moles per liter

Homework Equations


Not certain

The Attempt at a Solution


I was able to determine the alkalinity by finding the equivalent weight of CaCO3, 50 g/eq. I then converted 125 meq/L to eq/L. Then I multiplied (50 g/eq)(0.125 eq/L)(1000 mg/g) and got an answer of 6250 mg/L of CaCO3. I am having trouble approximating the total carbonate concentration. Could someone help please?
 
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What is the definition of alkalinity? How is it related to the carbonate concentration?
 
Well, alkalinity is the buffering capacity of the liquid. The resistance of the liquid to pH change. The greater the carbonate concentration the greater the buffering capacity.
 
Let me put it differently then. How is carbonate alkalinity measured and how - in result of the way it is measured - does it depend on the carbonate concentration?

I am not asking about qualitative description, but about a simple quantitative one.
 
I realize it is going to be something like this:

Alkalinity = (1 eq/mol)([HCO3]) + (2 eq/mol)([CO3]) + (1 eq/mol)([OH]) - (1 eq/mol)([H])

The influence of the OH and H are minimal and easy to calculate. [H+] = 10^(-7.8), [OH-] = (10^(-7.8))/(1 x 10^(-14))
 
Last edited:
I also know that ultimately we will get something like this:

Alkalinity = f1Ct + f2Ct + [OH-] - [H+]

f1 and f2 need to be calculated in order to ascertain Ct.
 
You start with pH of 7.8. What do you have to neutralize?

Note: I don't like the answer given, IMHO it is slightly off.
 
We have to neutralize an H+ donating acid.
 
Which is?

You are giving the simplest possible answer, one that doesn't require any insight, and you wait for another hint. Try harder.
 
  • #10
Carbonic Acid (H2CO3) I believe.
 

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