1. The problem statement, all variables and given/known data If the pH of a natural water is 7.8 and the alkalinity was measured to be 125 meq/L, determine the following: -Alkalinity as mg/L CaCO3: Answer = 6250 mg/l CaCO3 -Approximate the total carbonate concentration CT, in moles per liter: Answer = 0.125 moles per liter 2. Relevant equations Not certain 3. The attempt at a solution I was able to determine the alkalinity by finding the equivalent weight of CaCO3, 50 g/eq. I then converted 125 meq/L to eq/L. Then I multiplied (50 g/eq)(0.125 eq/L)(1000 mg/g) and got an answer of 6250 mg/L of CaCO3. I am having trouble approximating the total carbonate concentration. Could someone help please?