Phase changes and energy conservation

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SUMMARY

The discussion focuses on calculating the equilibrium temperature when a 35-g ice cube at 0.0 °C is added to 110 g of water in a 62 g aluminum cup at an initial temperature of 23 °C. The relevant equations include Q = mL for phase changes and Q = mc(change in T) for temperature changes, with specific heat capacities provided for water, ice, and aluminum. The equilibrium temperature must be determined by equating the heat gained by the ice and the heat lost by the water and cup. Additionally, replacing the aluminum cup with a silver cup will result in a higher equilibrium temperature due to silver's lower specific heat capacity.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with specific heat capacities (cwater, cice, caluminum)
  • Knowledge of phase change concepts (latent heat)
  • Ability to solve equations involving energy conservation
NEXT STEPS
  • Calculate equilibrium temperature using Q = mc(change in T) for different materials
  • Explore the effects of different specific heat capacities on thermal equilibrium
  • Investigate phase change calculations involving other substances
  • Learn about the principles of energy conservation in thermodynamic systems
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in heat transfer and phase change calculations.

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Homework Statement


A 35-g ice cube at 0.0 C is added to 110 g of water in a 62 g aluminum cup. The cup and the water have an initial temperature of 23 C.

a. Fine the equilibrium temperature of the cup and its contents

b. Suppose the aluminum cup is replaced with one of equal mass made from silver. Is the equilibrium temperature with the silver cup greater than, less than, or the same as with the aluminum cup? Explain.

Homework Equations


Q = mL
Q = mc(change in T)
cwater = 4186
cice = 2090
caluminum=900
Lice = 33.5 x 10^4

The Attempt at a Solution


]3. The Attempt at a Solution [/b]
I set the mL = [mwcw(Tfw-Tiw) + maca(Tfa - Tia)]
but that seems wrong, and there are another 20 steps after, so I'm going to not put that here
 
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When you made the energy gained equal the energy lost, you only took into account the phase change from ice to water (Q = mL). After it has made the change, it is now water at 0 degrees, right?
 

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