Two trumpeters are standing 3m apart and blowing in the same not at 932Hz. A listener stands directly infront of one of the trumpeters. 10m from the wall. Take the velocity of sound to be 340m/s.(adsbygoogle = window.adsbygoogle || []).push({});

i) what is the phase difference between the two waves when they reach the listener?

ii)what frequency closest to 932Hz would produce a minimum intensity at the listener?

I think i have part i down

what i did was (making p = phase constant and w wave length, dl change in distance)

p=2dLpi/w

v=fw

so

p = (2pi dL f) / v

and i got 52.4

then for part ii im not sure what to do, the equation for intensity involves power in my book

im not sure how to find power

thanks

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# Homework Help: Phase constant problem, two trumpets

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