Phase difference of 2 points in a same graph

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kelvin macks
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Homework Statement



since point P is ahead of point O, why the displacement , y , of P shouldn't be Asin(wt + 2pi/(x)) ?

Homework Equations





The Attempt at a Solution

 

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Be careful, the graph is against x not t.
 
Jilang said:
Be careful, the graph is against x not t.

sorry, stil don't unseratand . can you explain further?
 
kelvin macks said:

Homework Statement



since point P is ahead of point O, why the displacement , y , of P shouldn't be Asin(wt + 2pi/(x)) ?
Think of the figure as a snapshot photo of an ocean swell.

Imagine O and P are corks floating on the ocean, and they rise and fall as the wave gently passes. At the moment captured in the photo, cork O is falling and crossing the zero line. How far must the wave move along (sliding along to the right) before cork P in turn finds itself falling through the zero line?

So P is lagging O by ...?
 
NascentOxygen said:
Think of the figure as a snapshot photo of an ocean swell.

Imagine O and P are corks floating on the ocean, and they rise and fall as the wave gently passes. At the moment captured in the photo, cork O is falling and crossing the zero line. How far must the wave move along (sliding along to the right) before cork P in turn finds itself falling through the zero line?

So P is lagging O by ...?

so are you assuming falling downward dispalcement is positive? floating upward dispalcement is negative since you said P is lagging behind by O. how do we know which direction is positive and which is negative (falling downward or floating upward) ?
 
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kelvin macks said:
so are you assuming falling downward dispalcement is positive?
Defintely not assuming anything. I described how you could see things were you to imagine this as an ocean swell; I used an analogy.

Floating upward dispalcement is negative since you said P is lagging behind by O. how do we know which direction is positive and which is negative (falling downward or floating upward) ?
You are told that movement is described as A.sin(ωt), so that's where you might choose/assume '+' direction if it's not explicitly indicated.

Any and every motion of O will be emulated at a time Δt later by a point which lags O by that amount of time, regardless of what that instantaneous motion of the sinusoid may be. Whatever O is doing will be copied by P a short time later.
 
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