Phase Difference Problem, Ratio of I/Io

In summary, phase difference is the measure of how much two waveforms are shifted from each other and is related to the ratio of I/Io, representing the relative amplitude and direction of the waves. The phase difference problem is typically solved using mathematical equations and formulas, and the ratio of I/Io is significant in understanding the behavior and characteristics of waves. The ratio cannot be negative or greater than 1. Phase difference also affects the interference pattern of waves, with in-phase waves resulting in constructive interference and out-of-phase waves resulting in destructive interference.
  • #1
Lemmy
22
0

Homework Statement


What is the ratio of the intensity at this point to the intensity at the center of a bright bridge


Homework Equations


GIVEN:
Wavelength=6.9x10^-7m
d=0.00014m (distance between slits)
L=12m (Length to screen/point)
Y=14mm

EQUATION:
I=Io cos^2(phi/2) [(Sin (B/2))/(B/2)]
I/Io=cos^2(phi/2) [(Sin (B/2))/(B/2)]

The Attempt at a Solution




I have phi, solved for b/2 and plugged it in and did everything.

I STILL GOT IT WRONG??! is my equation wrong??
 
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  • #2
Where is "this point" and what's a "bright bridge"?
 
  • #3


I would like to first clarify the problem and make sure all the given information is correct. The problem mentions a "bright bridge" but does not specify what this means. Is this referring to a specific point on the screen or is it a term used in the context of the experiment? Additionally, the given values for wavelength, distance between slits, length to screen, and Y do not seem to be related to each other in a specific equation.

Assuming that the problem is referring to the intensity pattern of a double-slit experiment, the equation provided for I/Io is incorrect. The correct equation for the intensity at a point on the screen is given by I=4Io cos^2(πd sinθ/λ), where d is the distance between the slits, λ is the wavelength, and θ is the angle between the point on the screen and the center of the pattern.

If the problem is asking for the ratio of the intensity at a point on the screen to the intensity at the center of the pattern, then the equation would be I/Io=cos^2(πd sinθ/λ). However, without knowing the specific point on the screen, it is not possible to accurately calculate this ratio.

In order to solve this problem correctly, more information is needed, such as the specific point on the screen or the definition of the term "bright bridge". Additionally, it would be helpful to know the context of the experiment and what is being studied.
 

What is phase difference and how is it related to the ratio of I/Io?

Phase difference is the measure of how much two waveforms are shifted from each other. It is related to the ratio of I/Io because it represents the relative amplitude and direction of the waves at a given point in time.

How is the phase difference problem typically solved?

The phase difference problem is typically solved by using mathematical equations and formulas, such as the cosine law or trigonometric functions, to calculate the phase difference between two waveforms.

What is the significance of the ratio of I/Io in the study of phase difference?

The ratio of I/Io is significant in the study of phase difference because it represents the amplitude of the waves at a given point in time. This information is important in understanding the behavior and characteristics of the waves.

Can the ratio of I/Io be negative or greater than 1?

No, the ratio of I/Io cannot be negative or greater than 1. This is because the ratio represents the relative amplitude of the waves, and negative or greater than 1 values would not accurately reflect this.

How does the phase difference affect the interference pattern of waves?

The phase difference between two waves directly affects their interference pattern. If the waves are in phase (0 degrees phase difference), they will constructively interfere, resulting in a larger amplitude. If they are out of phase (180 degrees phase difference), they will destructively interfere, resulting in a smaller amplitude. This can create a variety of interference patterns depending on the phase difference between the waves.

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