Photoelectric and Compton Effects

In summary: In the photoelectric effect, the electron is absorbing a photon and the photon's energy and momentum are being redistributed so that they are still conserved. However, in the Compton effect, the electron is not absorbing the photon and its momentum and energy are not being redistributed. This is because the photon has no momentum in the Compton effect.
  • #1
Red_CCF
532
0
I was posting on another thread and it got me wondering: how come a photon is absorbed in the photoelectric effect but it is only partially absorbed in the Compton Effect? How come the electron in the Compton Effect does not absorb the photon entirely like the photoelectric effect? If photon is a particle as well how come it does not bounce off of a metal plate?

Thanks for any help that you can provide
 
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  • #2
In the Compton effect the photon cannot be completely absorbed because momentum and energy must be conserved. In the photoelectric effect, you have electrons in a metal which form a set of states with a continuous band of energies, so the system is much more flexible as to whether or not a photon can be absorbed. Not all the photons will be absorbed in the photoelectric effect, many will be scattered or reflected.
 
  • #3
kanato said:
In the Compton effect the photon cannot be completely absorbed because momentum and energy must be conserved.

Why would the collision be inelastic if the photon is completely absorbed?
 
  • #4
Work out the change in energy and momentum if the photon is completely absorbed:

Initial energy is energy of photon plus rest energy of electron (p is momentum of photon):

[tex]E_i = pc + mc^2[/tex]

Final energy is entirely the electron (p is now momentum of the electron):

[tex]E_f = \sqrt{(pc)^2 + (mc^2)^2}[/tex]

Set them equal and square and you get:

[tex](pc)^2 + 2 pmc^3 + (mc^2)^2 = (pc)^2 + (mc^2)^2[/tex]

Cancel terms until you get p = 0. This tells you that energy and momentum can only both be conserved if the photon has zero momentum, and hence zero energy, so there is no physically meaningful result.
 
  • #5
Also note that in the photoelectric effect, the "object" that the photon "collides" with is a multi-particle system, which makes for many ways to distribute the photon's energy and momentum so that they are still conserved in the end.
 
  • #6
kanato said:
Work out the change in energy and momentum if the photon is completely absorbed:

Initial energy is energy of photon plus rest energy of electron (p is momentum of photon):

[tex]E_i = pc + mc^2[/tex]

Final energy is entirely the electron (p is now momentum of the electron):

[tex]E_f = \sqrt{(pc)^2 + (mc^2)^2}[/tex]

Set them equal and square and you get:

[tex](pc)^2 + 2 pmc^3 + (mc^2)^2 = (pc)^2 + (mc^2)^2[/tex]

Cancel terms until you get p = 0. This tells you that energy and momentum can only both be conserved if the photon has zero momentum, and hence zero energy, so there is no physically meaningful result.

Thanks so much for clearing that up
 
  • #7
Red_CCF said:
Why would the collision be inelastic if the photon is completely absorbed?

Inelatic collision refers to depletion of photon energy
 

1. What is the photoelectric effect?

The photoelectric effect is a phenomenon where electrons are emitted from a metal surface when it is exposed to light of a certain frequency. This effect was first observed by Heinrich Hertz in 1887 and later explained by Albert Einstein in 1905.

2. How does the photoelectric effect demonstrate the particle nature of light?

The photoelectric effect shows that light behaves like a stream of particles, known as photons. This is because the number of electrons emitted from a metal surface depends on the intensity of the light, not the frequency. This is in contrast to the wave nature of light, where the frequency would determine the energy of the electrons emitted.

3. What is the Compton effect?

The Compton effect is a phenomenon where X-rays lose some of their energy when they collide with electrons in a material. This was first observed by Arthur Compton in 1923 and provided evidence for the particle nature of X-rays.

4. How does the Compton effect support the idea of photons?

The Compton effect shows that X-rays behave like particles, as they can transfer some of their energy to electrons during a collision. This supports the idea of photons, which are packets of energy that make up electromagnetic radiation.

5. What is the significance of the Photoelectric and Compton effects?

The Photoelectric and Compton effects are significant because they provide evidence for the particle nature of light and X-rays, which was a major breakthrough in understanding the behavior of electromagnetic radiation. These effects also have practical applications in technology, such as in photoelectric cells used in solar panels and in medical imaging techniques like Computed Tomography (CT) scans.

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