Photoelectric Cells: What Are They and Why Evacuated?

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Discussion Overview

The discussion centers on the functioning of photoelectric cells, specifically addressing the reason for their evacuated design. Participants explore the implications of gas presence on electron movement and current measurement.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions the necessity of evacuation in photoelectric cells, prompting others to consider the mechanics of electron movement.
  • Another participant elaborates on the process, noting that light of a certain frequency can free electrons from a metal surface, which then travel towards the positive cathode.
  • There is a suggestion that the presence of gases like oxygen could lead to collisions with electrons, potentially ionizing the gases and affecting current readings.
  • A later reply reiterates the concern that such collisions could result in no current reading at all.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the reasons for evacuating photoelectric cells, with multiple viewpoints regarding the impact of gas presence on electron behavior and current measurement remaining unresolved.

Contextual Notes

The discussion does not clarify the specific mechanisms by which gas presence affects electron movement or current readings, leaving assumptions about the nature of collisions and ionization unaddressed.

bael
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I was wondering why photoelectric cells are evacuated
 
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Think how they work.
 
Borek said:
Think how they work.

light of a certain frequency hits a metal and frees some electrons, which then travel toward the positive cathode.
 
So far so good. Now think about the "travel towards the cathode part".
 
Borek said:
So far so good. Now think about the "travel towards the cathode part".

is it because the electrons could possibly collide with the oxygen and other electronegative gases, ionizing them and thus giving a smaller reading on the current meter?
 
bael said:
is it because the electrons could possibly collide with the oxygen and other electronegative gases, ionizing them and thus giving a smaller reading on the current meter?

More precisely "giving no reading".
 

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