Photoelectric effect and continuous energy function

Click For Summary
SUMMARY

The discussion centers on the photoelectric effect, specifically the equation E=hf-W, where W represents the work function. It highlights that while E=hf-W is a continuous function, electrons in an atom are excited only by discrete frequencies, denoted as n*f0. This discrepancy raises questions about the nature of energy levels within conductors versus isolated metal atoms. The conversation suggests that in free space, a single metal atom would indeed respond to a limited set of discrete frequencies.

PREREQUISITES
  • Understanding of the photoelectric effect and its mathematical representation
  • Familiarity with quantum mechanics concepts, particularly energy quantization
  • Knowledge of work function in the context of electron excitation
  • Basic principles of atomic structure and electron behavior
NEXT STEPS
  • Explore the implications of the photoelectric effect on modern photovoltaic technologies
  • Study the relationship between energy levels and electron transitions in quantum mechanics
  • Investigate the role of work function in different materials and its impact on electron emission
  • Learn about the experimental setups used to demonstrate the photoelectric effect
USEFUL FOR

Physics students, researchers in quantum mechanics, and professionals in materials science focusing on electron behavior and energy transitions.

kidsasd987
Messages
142
Reaction score
4
TL;DR
E=hf-W where W is a work function.

However we know that electrons in an atom will be excited only when radiated with photons of n*f0 discrete number of frequencies.

where E=hf-W is a continuous function. hows is that possible?
E=hf-W where W is a work function.

However we know that electrons in an atom will be excited only when radiated with photons of n*f0 discrete number of frequencies.
where E=hf-W is a continuous function.

Is this because energy level is continuous within a conductor?
If we think of only one metal atom in free space, then it will only take n*f0 discrete number of frequencies, right?
 
Engineering news on Phys.org

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
3
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K