Photon 4-Momentum in SR: Why Must it Transform?

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SUMMARY

The discussion centers on the transformation of the 4-momentum for photons, defined as pμ = (hν/c, hν/c &textbf{e}). It is established that the 4-momentum transforms as a 4-vector in Special Relativity for all particles, not exclusively for photons. Participants confirm that applying an arbitrary Lorentz transformation validates this transformation property. The derivation process involves setting pμ = (p0, &vec;p) and applying the Lorentz transformation to ascertain the correct form of p0.

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Why must the 4-momentum for photons [tex]p^\mu =(\frac{h\nu}{c},\frac{h\nu}{c} \textbf{e})[/tex] transform as a 4-vector in Special Relativity?
 
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I don't understand the question. The four-momentum transforms as a four-vector for all particles, not just photons.
 
And if you apply an arbitrary Lorentz transformation, you can easily check that it does.
You can even derive it (Let [itex]p^\mu = (p^0, \vec{p})[/itex], apply a Lorentz transformation and you will see what p0 should be).
 

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