Photon Acceleration Near Gravitational Fields

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Discussion Overview

The discussion centers on whether photons experience acceleration when they are near gravitational fields, particularly in the context of black holes and general relativity. Participants explore the implications of gravity on the direction and speed of light, as well as the definitions of acceleration in this context.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants argue that gravity affects the energy of light but does not change its speed, suggesting that while the direction of light can change, this does not constitute acceleration in the traditional sense.
  • Others propose that changing the direction of a photon implies a change in velocity, which could be interpreted as acceleration, drawing parallels to uniform circular motion.
  • A participant mentions that in general relativity, gravity is not a force but rather the curvature of spacetime, which leads to photons following curved paths or geodesics.
  • There is a discussion about the distinction between "proper acceleration" and "coordinate acceleration," with some participants noting that definitions may vary and affect interpretations of acceleration in this context.
  • One participant references the Shapiro delay and provides an equation related to the local speed of light, indicating a complex relationship between gravity and light's behavior.
  • Another participant expresses confusion about the implications of following a geodesic and whether this constitutes a change in direction or acceleration.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether photons experience acceleration in gravitational fields. Multiple competing views remain, with some asserting that direction change equates to acceleration, while others maintain that the speed of light remains constant and thus does not imply acceleration in the traditional sense.

Contextual Notes

Discussions involve various interpretations of acceleration, the nature of gravity in general relativity, and the behavior of light in gravitational fields. Some assumptions about definitions and the nature of forces may not be fully articulated, leading to different conclusions among participants.

big_bounce
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Hello all ,

When a photon gets closer and closer to black hole , gravity affects photon and changes direction of photon's moving .
Is that mean photon gets acceleration near gravitational field ?

Thanks.
 
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No. Gravity affects, directly, an object's energy. For "massive" objects, that means primarily its kinetic energy and so its speed. For light, which has no mass, the energy is plank's constant, h, times the speed of light, c, divided by the wave length of the light. h and c are constants so, if the energy increases, the wavelength decreases.
 
Yes, obviously light flying by a massive body changes direction and hence is accelerated, at least transversally. However the gravitational interaction with light is more complicated than with massive bodies. E.g. two light beam traveling parallel to each other won't attract each other but counter propagating rays do.
 
Light always travel at a constant speed 'c' locally in a vacuum...and it always follows a null geodesic [space-time path].

See 'gravitational lensing',

http://en.wikipedia.org/wiki/Gravitational_lensing

You can also read about the energy of light via 'gravitational redshift' or 'gravitational blueshift'...
 
big_bounce said:
Is that mean photon gets acceleration near gravitational field ?

The acceleration is

[itex]\vec a = \frac{2}{u} \cdot \vec v \cdot \left( {\vec v \cdot grad\;u} \right) - u \cdot grad\;u[/itex]

where u is the "local speed of light" according to the Shapiro delay.
 
Any more idea ?
I didn't get clear answer .
Yes or no ?

HallsofIvy said:
No. Gravity affects, directly, an object's energy. For "massive" objects, that means primarily its kinetic energy and so its speed. For light, which has no mass, the energy is plank's constant, h, times the speed of light, c, divided by the wave length of the light. h and c are constants so, if the energy increases, the wavelength decreases.

I didn't talking about energy of photon .
I just want to know , does it get acceleration or not ?
If not , why ?
According to Newton's first law of motion we know objects in motion tend to stay in motion with the same speed and the same direction unless acted upon by an unbalanced force.
If we consider gravity a force, gravity must change direction of photon's moving .

Thank you


Naty1 said:
Light always travel at a constant speed 'c' locally in a vacuum...and it always follows a null geodesic [space-time path].

See 'gravitational lensing',

http://en.wikipedia.org/wiki/Gravitational_lensing

You can also read about the energy of light via 'gravitational redshift' or 'gravitational blueshift'...

So you say when gravity affects photon , photon didn't changing it's direction and just follow space-time path ? and follow space-time path does not mean changing direction ?
Thank you

DrStupid said:
The acceleration is

[itex]\vec a = \frac{2}{u} \cdot \vec v \cdot \left( {\vec v \cdot grad\;u} \right) - u \cdot grad\;u[/itex]

where u is the "local speed of light" according to the Shapiro delay.
I searched internet but i couldn't find this equation
Can you give a link from University website ?
Thank you .
 
Last edited:
Quote by Naty1
Light always travel at a constant speed 'c' locally in a vacuum...and it always follows a null geodesic [space-time path].

See 'gravitational lensing',

http://en.wikipedia.org/wiki/Gravitational_lensing

You can also read about the energy of light via 'gravitational redshift' or 'gravitational blueshift'...

So you say when gravity affects photon , photon didn't changing it's direction and just follow space-time path ?

I'm not sure what you are saying here..it seems self contradictory.

Did you read the definition of a 'geodesic' or the link to 'gravitational lensing' ? They explain in more detail.

Gravity does cause a photon to follow a curved path when viewed from a distance...

and follow space-time path does not mean changing direction?

It can do both.
 
I just want to know , does it get acceleration or not ?
If not , why ?

yes, because the direction is changed, hence the velocity direction...but not the speed...

uniform circular motion, as an example, such as the rotation on the circumference of a rotating circle has constant acceleration and speed...but we say the velocity is constantly changing because the direction of motion is constantly changing.
 
The answer depends a bit on the question you are asking and the level at which you are asking it.

The speed of the light does not change in a gravitational field, if that is what you are asking. Instead, its wavelength and frequency change as HallsOfIvy said. However, light can change direction and you might call that an acceleration. Certainly it would be called an acceleration by Newton, but Newton's theory of gravity provides no mechanism for gravity to interact with light.

General Relativity does provide a mechanism, but it's a bit more complex. In GR, gravity is not a force. It is the geometry of spacetime. The basic concept is that everything moves along paths called "geodesics" unless there is a force acting. If there's no gravity, geodesics are straight lines, and objects move in straight lines. When there is gravity, geodesics are curved lines so objects follow curved paths (for example, the trajectory of a thrown ball is a geodesic). Whether or not following that curved path is an acceleration depends on your definition of acceleration - some people make a distinction between "proper acceleration" (when a force is acting) and "coordinate acceleration" (when spacetime is a funny shape) to avoid confusion.

Is that a straight enough answer? Or was it a curved geodesic? :smile:
 
  • #10
big_bounce said:
I searched internet but i couldn't find this equation

I derived it for gradient-index optics using the Huygens–Fresnel principle. Unfortunately I didn't kept the calculation. I just remember it was a little bit tricky.
 
  • #11
Ibix said:
Is that a straight enough answer? Or was it a curved geodesic? :smile:

Good explanation .
Thanks for giving me your time and thanks all .
 

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