Demystifier said:
This is not that simple. For example, in nonrelativistic QFT, you CAN introduce a state that corresponds to a localized particle. You can also introduce a state that corresponds to a localized field. However, these two states are VERY different. In particular, the former is a 1-particle state, whereas the latter is a coherent state with an indefinite number of particles. So no, particles and fields are NOT just two different names for the same thing.
I don't know why you're so keen on nonrelativistic theory, it's just an approximation.
Let's talk more specifically about "relativistic" gauge theory. You have a wave functional that assigns to every gauge field configuration a complex number which you could consider as defining the probability density for having that gauge field configuration:
\Psi: A\to \Psi[A] with \Psi^*[A]\Psi[A]= probability density to find configuration A
So if you have detected a grain of silver on your photographic plate, you know definitely that the gauge field must have been in some configuration A_0 that was localized around the site of your grain of silver somewhere during or immediately after producing the latter.
So your wave functional \Psi[A] which has originally contained the possibility for many different gauge field configurations has now collapsed to a wave functional \Psi_0[A] such that
\Psi[A] = \left\{ \begin{array}{cr} \infty & \qquad A=A_0 \\<br />
0 & \qquad otherwise \end{array}\right.
where I have introduced a symbolical definition of a "delta-function over function space".
Now where is the need to define something like a position operator here ? If you like to, you may define position as the weighted average of the usual position operator "x" over the electromagnetic energy of your localized gauge field configuration A0:
\bar{x}[A_0]=\frac{\int x T^{00}(F(A_0)) d^4 x}{\int T^{00} d^4 x}
You will not be surprised that this provides you with the position of your grain of silver. So what further insight does this give you ?