Physical meaning of equations of equilibrium

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Discussion Overview

The discussion centers around the physical meaning of the equations of equilibrium, particularly focusing on the expression involving the force in the y-direction and its components, including the role of partial derivatives. Participants explore the implications of these mathematical concepts in the context of aeronautical engineering and seek clarification on their physical interpretations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant queries the physical meaning of the term involving the partial derivative of σy with respect to y, multiplied by a small change in y (δy).
  • Another participant clarifies that δy represents a small change in y and that the partial derivative indicates dependence on other variables, emphasizing that the physical meaning is context-dependent.
  • A later reply acknowledges a typo in the original question and provides context about the expression being part of a derivation in a specific textbook.
  • Some participants suggest that the mathematical concepts, such as partial derivatives, can be complex, especially in the context of aerodynamics.
  • One participant expresses a desire for resources to better understand the physical meanings of differentiation and its applications, indicating a background in solving differential equations but lacking in conceptual understanding.
  • Another participant discusses the variability of physical meanings depending on the context, providing examples of derivatives in physics, such as velocity and acceleration.
  • There is a suggestion that a memorization approach to learning may not be sufficient at advanced levels of study, advocating for a deeper understanding of the underlying concepts.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the physical meanings of mathematical expressions, with no consensus reached on a definitive explanation. The discussion reflects multiple perspectives on the interpretation of derivatives and their applications in physics.

Contextual Notes

Limitations include the dependence on specific contexts for the physical meanings of mathematical expressions, as well as the unresolved nature of how different participants interpret the relationship between mathematics and physical phenomena.

Who May Find This Useful

This discussion may be useful for students in aeronautical engineering or related fields who seek to deepen their understanding of the physical implications of mathematical concepts, particularly in the context of equations of equilibrium and differentiation.

Aravind Raj
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From the equations of equilibrium
"σy+(∂σy/∂y)*(lower case delta y)" is the force acting along y direction. can anybody explain the physical meaning of the second part of the force where we multiply delta and del?
 
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Welcome to PF;
What is your education level?

Do you mean: $$\sigma_y + \left[\frac{\partial \sigma_y}{\partial y}\right]\delta y$$ ... in which case, "we" do not "multiply delta and del".

##\delta y## is one variable and reads: "a small change in y"
##\partial## implies a partial derivative. It means that ##\sigma_y## may depend on variables other than y
In the above expression, the partial derivative of ##\sigma_y## with respect to y is being multiplied by a small change in y. This product is added to ##\sigma_y##.
The physical meaning depends on context.

There are many equations of equilibrium: where did you find that particular expression?
 
Simon Bridge said:
Welcome to PF;
What is your education level?

Do you mean: $$\sigma_y + \left[\frac{\partial \sigma_y}{\partial y}\right]\delta y$$ ... in which case, "we" do not "multiply delta and del".

##\delta y## is one variable and reads: "a small change in y"
##\partial## implies a partial derivative. It means that ##\sigma_y## may depend on variables other than y
In the above expression, the partial derivative of ##\sigma_y## with respect to y is being multiplied by a small change in y. This product is added to ##\sigma_y##.
The physical meaning depends on context.

There are many equations of equilibrium: where did you find that particular expression?
I know we don't multiply del and delta, typo while expressing my doubt. Thanks for explaining it. Its a part of derivation for equation of equilibrium. Book: Aircraft structures by MegsonALSO CAN U SUGGEST ANY BOOKS TO UNDERSTAND BASICS OF CALCULUS, DIFFERENTIATION ?
 
OK - so it's probably something to do with airflows ... in the text of the book by the equation it should have told you what the different symbols mean.
A partial derivative is not the same as "a part of derivative" - the maths of aircraft is usually very complicated.

Note: you can take an online beginning calculus course - best value for money.
I cannot possibly advise you on which one or which text will help you because I don't know your education background so far.
Have a look at: http://nrich.maths.org/4722 see if it's too easy of too hard.
 
Simon Bridge said:
OK - so it's probably something to do with airflows ... in the text of the book by the equation it should have told you what the different symbols mean.
A partial derivative is not the same as "a part of derivative" - the maths of aircraft is usually very complicated.

Note: you can take an online beginning calculus course - best value for money.
I cannot possibly advise you on which one or which text will help you because I don't know your education background so far.
Have a look at: http://nrich.maths.org/4722 see if it's too easy of too hard.
I'm doing my 3rd year Aeronautical engineering. The way I've been taught in my school and college, I can solve almost all the differential equations, I know the formulae ,partial differentiation etc. I don't know the physical meanings of those differentiations. so i want a book that can help me with understanding the applications and physical meaning.
 
The physical meaning depends on the context ... like all maths.

For instance - if the function represents a surface, then the slope of the surface in a particular direction is the derivative of the function along that direction.

Put most simply:
The derivative is how much something is changing with the variable the derivative is taken against.
What that means depends on the something and the variable.

Simplest example is that the time-derivative of the displacement is the velocity, and the time-derivative of the velocity is the acceleration.
More tricky: the space-derivative of work is the force - which is also the time derivative of momentum.See the problem with answering your question?
I don't think there are any books covering this topic - it's too variable.
 
Simon Bridge said:
The physical meaning depends on the context ... like all maths.

For instance - if the function represents a surface, then the slope of the surface in a particular direction is the derivative of the function along that direction.

Put most simply:
The derivative is how much something is changing with the variable the derivative is taken against.
What that means depends on the something and the variable.

Simplest example is that the time-derivative of the displacement is the velocity, and the time-derivative of the velocity is the acceleration.
More tricky: the space-derivative of work is the force - which is also the time derivative of momentum.See the problem with answering your question?
I don't think there are any books covering this topic - it's too variable.
okay. thanks. I will go thru the basics again and understand the concepts instead of just memorising. :D
 
That's the idea - you can go a long way in your education on memorization skills alone but usually this trips people up at senior undergrad level at the latest.
If you studied pure science the "memorization" approach would have tripped you up much sooner.

The trick is to see the maths as a language.
 

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