High School Physical significance of wave function

Click For Summary
SUMMARY

The discussion centers on the physical significance of the wave function in quantum mechanics, particularly as introduced in D. J. Griffiths' textbook. The wave function, denoted as ψ(x), is established as a mathematical representation of probability density, with its square providing the probability distribution for measuring physical quantities. The normalization condition, expressed as ∫ d³x ψ*(x) ψ(x) = 1, confirms that the wave function serves as a factorization of this probability distribution. While the wave function itself is not a directly measurable physical quantity, it is essential for understanding quantum systems.

PREREQUISITES
  • Understanding of quantum mechanics fundamentals
  • Familiarity with D. J. Griffiths' "Introduction to Quantum Mechanics"
  • Knowledge of probability density functions
  • Basic grasp of normalization conditions in mathematical physics
NEXT STEPS
  • Study the implications of the normalization condition in quantum mechanics
  • Explore the role of the Schrödinger equation in wave function analysis
  • Investigate experimental methods for measuring quantum states
  • Learn about the interpretation of wave functions in different quantum theories
USEFUL FOR

Students and enthusiasts of quantum mechanics, particularly those seeking to deepen their understanding of wave functions and their applications in physical systems.

Wrichik Basu
Science Advisor
Insights Author
Gold Member
Messages
2,180
Reaction score
2,690
I am a beginner in quantum mechanics. I started out with D. J. Griffiths' book in quantum mechanics.

I'm having a problem in understanding the wave function. What is the physical meaning of the wave function? I searched on the net but didn't get any good explanation. I understand that the square of the wave function represents probability density. I also understood the normalisation of wave function, but what is the wave function by itself? How can I experimentally find a wave function?
 
Last edited:
Physics news on Phys.org
Wrichik Basu said:
didn't get any good explanation.
there is none. No physical meaning. Nevertheless very useful (as in the Schroedinger equation)
I understand that the square of the wave function represents probability
In fact it is a probability density.
 
From the normalization condition ## \int \mathrm{d}^3 x \psi^*(x) \psi(x) = 1## you can see the wave function is in some sense the square root or factorization of a probability distribution, it is a means for representing probabilities for measuring quantities related to physical systems.
 
formodular said:
From the normalization condition ## \int \mathrm{d}^3 x \psi^*(x) \psi(x) = 1## you can see the wave function is in some sense the square root or factorization of a probability distribution, it is a means for representing probabilities for measuring quantities related to physical systems.
Yes, that I've seen. I was looking forward to whether it was a physical quantity which can be measured.
 
BvU said:
In fact it is a probability density.
Thanks for that, I had missed it!
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 61 ·
3
Replies
61
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
8K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K