Physics 12: Power Output Calculation for Accelerating Object

[gdhillon]

A 5.0 kg object is accelerated from rest to 6.0 m/s while moving 2.0 m across a level
surface. If the force of friction is 4.0 N, calculate the power output



I used d=vt to find the time which was .33sec then i put that into P=Fd/t and had (49-4)(2)/.35 and got 270 Watts

 

[Simon Bridge]

Cool - was there a question in all that?
Is there some role the v-t graph could play?

 

[dreamLord]

d = vt is applicable only for constant velocities. The object is accelerating in this case. You must use a kinematics equation to find the time - you know the initial and final velocities, and the distance traveled.