1. in a tire-throwing competition, a man holding a 23.5 kg car tire quickly swings the tire through three full turns and releases it, much like a discus thrower. the tire starts from rest and is then accelerated in a circular path. the orbital radius "r" for the tire's center of mass is 1.10 m, and the path is horizontal to the ground. the man applies a constant torque of 20.0 N m to accelerate the tire at a constant angular acceleration. Assume that all of the tire's mass is at a radius R = 0.35 m from its center. what is the time, t, required for the tire to complete three full revolutions? 2. T=[2(pi)(r)]/v Torque = Inertia * angular acceleration 3. T=Inertia * angular acceleration T=Inertia * (linear acceleration/radius) T=Inertia * (linear velocity^2/radius^2) 20=[(23.5*.35^2)]*(linear velocity^2/.75^2) linear velocity = 2.9 m/s T=[2(pi)(1.1)]/2.9 = 2.38 2.38 * 3 revolutions = 7.15 I think the problem is my radius, I don't know which ones im supposed to use. the answer is supposed to be 7.68s, but im close with 7.15. can someone tell me what im doing wrong?