Physics - Determine Pith Ball Charges

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To determine the charge on each pith ball, the problem involves two equally charged balls, each with a mass of 1.5g, where one is suspended and the other is brought close, creating an equilibrium state. The distance between the balls is 2.6cm, and the thread holding the suspended ball forms a 20-degree angle with the vertical. The relevant equation for the force between the charges is F = (kQ1Q2)/(r^2). To solve the problem, a diagram illustrating the forces acting on the suspended ball is necessary, along with the application of equilibrium conditions, where the sum of vertical and horizontal forces equals zero. This approach will lead to the calculation of the charge on each pith ball.
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Homework Statement


Two pith balls equally charged and each with mass of 1.5g. While one ball is suspended by a thread, the other is brought close to it and a state of equilibrium is reached. In that situation, the two balls are separated by 2.6cm and the thread is attached to the suspended ball makes an angle of 20deg with the vertical. Calculate the charge on each of the pith balls.

m = 1.5*10^-3kg
d = 0.026m


Homework Equations


F = (kQ1Q2)/(r2)


The Attempt at a Solution


I tried finding the force by the work done formula since we have an angle we could include, but i do not get any further than that.
 
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I don't think you can get it that way because you have no means of calculating the work done by the hand pushing the stationary ball.
Use forces. Begin with a diagram of the three forces on the suspended ball when equilibrium is reached. Then write that the sum of the vertical forces is zero and the sum of the horizontal forces is zero (because F=ma and there is no acceleration).
 
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